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Say why item 14's repeat over {digits(1)} changes nothing

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Lilleman auf Larv
2026-10-05 07:46:27 +02:00
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@@ -374,7 +374,7 @@ Require the path step to reach a sibling category.
### 14. Spell `misc.creditcard`'s digit runs `{digits(n)}`, and refuse a repeat over a lone `{digits(1)}` at `New`, naming that spelling.
Both render the same run.
A repeat of 14 over `{digits(1)}` draws every 14-digit run with the odds `{digits(14)}` does, so under goal 5.7 the repeat is a wrapper that changes nothing.
### 38. Compare `calcParser.binary`'s operator as a rune.