51 lines
1.4 KiB
Go
51 lines
1.4 KiB
Go
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package utils
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import (
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"math/rand"
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"strings"
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"time"
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"golang.org/x/crypto/bcrypt"
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)
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const letterBytes = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"
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const (
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letterIdxBits = 6 // 6 bits to represent a letter index
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letterIdxMask = 1<<letterIdxBits - 1 // All 1-bits, as many as letterIdxBits
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letterIdxMax = 63 / letterIdxBits // # of letter indices fitting in 63 bits
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)
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var src = rand.NewSource(time.Now().UnixNano())
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// CheckPasswordHash checks a password hash
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func CheckPasswordHash(password, hash string) bool {
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err := bcrypt.CompareHashAndPassword([]byte(hash), []byte(password))
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return err == nil
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}
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// HashPassword hashes a password
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func HashPassword(password string) (string, error) {
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bytes, err := bcrypt.GenerateFromPassword([]byte(password), 14)
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return string(bytes), err
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}
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// RandString generates a random string. Taken from https://stackoverflow.com/questions/22892120/how-to-generate-a-random-string-of-a-fixed-length-in-go (RandStringBytesMaskImprSrcSB())
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func RandString(n int) string {
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sb := strings.Builder{}
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sb.Grow(n)
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// A src.Int63() generates 63 random bits, enough for letterIdxMax characters!
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for i, cache, remain := n-1, src.Int63(), letterIdxMax; i >= 0; {
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if remain == 0 {
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cache, remain = src.Int63(), letterIdxMax
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}
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if idx := int(cache & letterIdxMask); idx < len(letterBytes) {
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sb.WriteByte(letterBytes[idx])
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i--
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}
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cache >>= letterIdxBits
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remain--
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}
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return sb.String()
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}
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